131201204343440 has 320 divisors, whose sum is σ = 387229907128320. Its totient is φ = 40151827077120.

The previous prime is 131201204343439. The next prime is 131201204343491. The reversal of 131201204343440 is 44343402102131.

It is a junction number, because it is equal to n+sod(n) for n = 131201204343397 and 131201204343406.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 298891802 + ... + 299330438.

It is an arithmetic number, because the mean of its divisors is an integer number (1210093459776).

Almost surely, 2^{131201204343440} is an apocalyptic number.

131201204343440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131201204343440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (193614953564160).

131201204343440 is an abundant number, since it is smaller than the sum of its proper divisors (256028702784880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131201204343440 is a wasteful number, since it uses less digits than its factorization.

131201204343440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 439550 (or 439544 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 131201204343440 its reverse (44343402102131), we get a palindrome (175544606445571).

The spelling of 131201204343440 in words is "one hundred thirty-one trillion, two hundred one billion, two hundred four million, three hundred forty-three thousand, four hundred forty".