131201233142113 has 2 divisors, whose sum is σ = 131201233142114. Its totient is φ = 131201233142112.

The previous prime is 131201233142059. The next prime is 131201233142141. The reversal of 131201233142113 is 311241332102131.

It is a happy number.

It is an a-pointer prime, because the next prime (131201233142141) can be obtained adding 131201233142113 to its sum of digits (28).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131197506405904 + 3726736209 = 11454148^2 + 61047^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131201233142113 is a prime.

It is a super-2 number, since 2×131201233142113² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131201233142513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600616571056 + 65600616571057.

It is an arithmetic number, because the mean of its divisors is an integer number (65600616571057).

Almost surely, 2^{131201233142113} is an apocalyptic number.

It is an amenable number.

131201233142113 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201233142113 is an equidigital number, since it uses as much as digits as its factorization.

131201233142113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 28.

Adding to 131201233142113 its reverse (311241332102131), we get a palindrome (442442565244244).

The spelling of 131201233142113 in words is "one hundred thirty-one trillion, two hundred one billion, two hundred thirty-three million, one hundred forty-two thousand, one hundred thirteen".