1312013031101 has 2 divisors, whose sum is σ = 1312013031102. Its totient is φ = 1312013031100.

The previous prime is 1312013031097. The next prime is 1312013031233. The reversal of 1312013031101 is 1011303102131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1096135711225 + 215877319876 = 1046965^2 + 464626^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312013031101 - 2² = 1312013031097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1312013031101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312013031701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656006515550 + 656006515551.

It is an arithmetic number, because the mean of its divisors is an integer number (656006515551).

Almost surely, 2^{1312013031101} is an apocalyptic number.

It is an amenable number.

1312013031101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312013031101 is an equidigital number, since it uses as much as digits as its factorization.

1312013031101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1312013031101 its reverse (1011303102131), we get a palindrome (2323316133232).

The spelling of 1312013031101 in words is "one trillion, three hundred twelve billion, thirteen million, thirty-one thousand, one hundred one".