Base | Representation |
---|---|
bin | 11000011100000010… |
… | …10101000000011111 |
3 | 1020212100211201100121 |
4 | 30032001111000133 |
5 | 203332223143403 |
6 | 10005521535411 |
7 | 643062163042 |
oct | 141601250037 |
9 | 36770751317 |
10 | 13120131103 |
11 | 5622a76762 |
12 | 2661aa4567 |
13 | 13112434b1 |
14 | 8c66bac59 |
15 | 51bc813bd |
hex | 30e05501f |
13120131103 has 2 divisors, whose sum is σ = 13120131104. Its totient is φ = 13120131102.
The previous prime is 13120131097. The next prime is 13120131119. The reversal of 13120131103 is 30113102131.
It is an a-pointer prime, because the next prime (13120131119) can be obtained adding 13120131103 to its sum of digits (16).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13120131103 - 217 = 13120000031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13120131403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560065551 + 6560065552.
It is an arithmetic number, because the mean of its divisors is an integer number (6560065552).
Almost surely, 213120131103 is an apocalyptic number.
13120131103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120131103 is an equidigital number, since it uses as much as digits as its factorization.
13120131103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 13120131103 its reverse (30113102131), we get a palindrome (43233233234).
The spelling of 13120131103 in words is "thirteen billion, one hundred twenty million, one hundred thirty-one thousand, one hundred three".
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