Base | Representation |
---|---|
bin | 11101110101001110110101… |
… | …000101000101100010100101 |
3 | 122012112201202102121000020212 |
4 | 131311032311011011202211 |
5 | 114144100433411003141 |
6 | 1143013032023105205 |
7 | 36430663046211266 |
oct | 3565166505054245 |
9 | 565481672530225 |
10 | 131201404000421 |
11 | 38894226165647 |
12 | 1286b8648a2205 |
13 | 58293159bc471 |
14 | 2458278d5a96d |
15 | 1027cb26692eb |
hex | 7753b51458a5 |
131201404000421 has 2 divisors, whose sum is σ = 131201404000422. Its totient is φ = 131201404000420.
The previous prime is 131201404000361. The next prime is 131201404000427. The reversal of 131201404000421 is 124000404102131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76463394592225 + 54738009408196 = 8744335^2 + 7398514^2 .
It is a cyclic number.
It is not a de Polignac number, because 131201404000421 - 214 = 131201403984037 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131201404000427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600702000210 + 65600702000211.
It is an arithmetic number, because the mean of its divisors is an integer number (65600702000211).
Almost surely, 2131201404000421 is an apocalyptic number.
It is an amenable number.
131201404000421 is a deficient number, since it is larger than the sum of its proper divisors (1).
131201404000421 is an equidigital number, since it uses as much as digits as its factorization.
131201404000421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 131201404000421 its reverse (124000404102131), we get a palindrome (255201808102552).
The spelling of 131201404000421 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred four million, four hundred twenty-one", and thus it is an aban number.
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