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131201404000421 is a prime number
BaseRepresentation
bin11101110101001110110101…
…000101000101100010100101
3122012112201202102121000020212
4131311032311011011202211
5114144100433411003141
61143013032023105205
736430663046211266
oct3565166505054245
9565481672530225
10131201404000421
1138894226165647
121286b8648a2205
1358293159bc471
142458278d5a96d
151027cb26692eb
hex7753b51458a5

131201404000421 has 2 divisors, whose sum is σ = 131201404000422. Its totient is φ = 131201404000420.

The previous prime is 131201404000361. The next prime is 131201404000427. The reversal of 131201404000421 is 124000404102131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76463394592225 + 54738009408196 = 8744335^2 + 7398514^2 .

It is a cyclic number.

It is not a de Polignac number, because 131201404000421 - 214 = 131201403984037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131201404000427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600702000210 + 65600702000211.

It is an arithmetic number, because the mean of its divisors is an integer number (65600702000211).

Almost surely, 2131201404000421 is an apocalyptic number.

It is an amenable number.

131201404000421 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201404000421 is an equidigital number, since it uses as much as digits as its factorization.

131201404000421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 131201404000421 its reverse (124000404102131), we get a palindrome (255201808102552).

The spelling of 131201404000421 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred four million, four hundred twenty-one", and thus it is an aban number.