Base | Representation |
---|---|
bin | 1011111011101100010101… |
… | …1001111000111100110011 |
3 | 1201110021101020220112010212 |
4 | 2332323011121320330303 |
5 | 3204430022324123103 |
6 | 43523150545014335 |
7 | 2522620231050425 |
oct | 276730531707463 |
9 | 51407336815125 |
10 | 13120142020403 |
11 | 41a9248146950 |
12 | 157a9310243ab |
13 | 7422bb409612 |
14 | 33503817a815 |
15 | 17b441d427d8 |
hex | beec5678f33 |
13120142020403 has 16 divisors (see below), whose sum is σ = 14370442595712. Its totient is φ = 11879438400000.
The previous prime is 13120142020387. The next prime is 13120142020457. The reversal of 13120142020403 is 30402024102131.
It is a cyclic number.
It is not a de Polignac number, because 13120142020403 - 24 = 13120142020387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13120142020483) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 90579548 + ... + 90724278.
It is an arithmetic number, because the mean of its divisors is an integer number (898152662232).
Almost surely, 213120142020403 is an apocalyptic number.
13120142020403 is a deficient number, since it is larger than the sum of its proper divisors (1250300575309).
13120142020403 is a wasteful number, since it uses less digits than its factorization.
13120142020403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 177826.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13120142020403 its reverse (30402024102131), we get a palindrome (43522166122534).
The spelling of 13120142020403 in words is "thirteen trillion, one hundred twenty billion, one hundred forty-two million, twenty thousand, four hundred three".
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