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131202220031 is a prime number
BaseRepresentation
bin111101000110001000…
…0101111111111111111
3110112122201010100110122
41322030100233333333
54122200232020111
6140135022525155
712323212320011
oct1721420577777
9415581110418
10131202220031
1150708261903
12215174367bb
13c4abc9562c
1464c90161b1
15362d68bcdb
hex1e8c42ffff

131202220031 has 2 divisors, whose sum is σ = 131202220032. Its totient is φ = 131202220030.

The previous prime is 131202220013. The next prime is 131202220063. The reversal of 131202220031 is 130022202131.

Together with previous prime (131202220013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131202220031 - 226 = 131135111167 is a prime.

It is a super-2 number, since 2×1312022200312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131202219991 and 131202220009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131202220001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601110015 + 65601110016.

It is an arithmetic number, because the mean of its divisors is an integer number (65601110016).

Almost surely, 2131202220031 is an apocalyptic number.

131202220031 is a deficient number, since it is larger than the sum of its proper divisors (1).

131202220031 is an equidigital number, since it uses as much as digits as its factorization.

131202220031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 131202220031 its reverse (130022202131), we get a palindrome (261224422162).

The spelling of 131202220031 in words is "one hundred thirty-one billion, two hundred two million, two hundred twenty thousand, thirty-one".