Base | Representation |
---|---|
bin | 10011000101111011001… |
… | …001111100110010100101 |
3 | 11122102120201020022122112 |
4 | 103011323021330302211 |
5 | 132444014443344031 |
6 | 2442423330410405 |
7 | 163535233312121 |
oct | 23057311746245 |
9 | 4572521208575 |
10 | 1312031231141 |
11 | 46647a475224 |
12 | 192344730a05 |
13 | 96954875417 |
14 | 477073b6581 |
15 | 241e02b462b |
hex | 1317b27cca5 |
1312031231141 has 4 divisors (see below), whose sum is σ = 1312503697452. Its totient is φ = 1311558764832.
The previous prime is 1312031230949. The next prime is 1312031231153. The reversal of 1312031231141 is 1411321302131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 659215710241 + 652815520900 = 811921^2 + 807970^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312031231141 - 214 = 1312031214757 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312031233141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236228990 + ... + 236234543.
It is an arithmetic number, because the mean of its divisors is an integer number (328125924363).
Almost surely, 21312031231141 is an apocalyptic number.
It is an amenable number.
1312031231141 is a deficient number, since it is larger than the sum of its proper divisors (472466311).
1312031231141 is an equidigital number, since it uses as much as digits as its factorization.
1312031231141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 472466310.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 1312031231141 its reverse (1411321302131), we get a palindrome (2723352533272).
The spelling of 1312031231141 in words is "one trillion, three hundred twelve billion, thirty-one million, two hundred thirty-one thousand, one hundred forty-one".
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