Base | Representation |
---|---|
bin | 11101110101010000100010… |
… | …101101010000000100111111 |
3 | 122012112220111121110100201022 |
4 | 131311100202231100010333 |
5 | 114144113220232332022 |
6 | 1143013534324334355 |
7 | 36431056451432051 |
oct | 3565204255200477 |
9 | 565486447410638 |
10 | 131203243245887 |
11 | 38894a8a394a1a |
12 | 128700988443bb |
13 | 5829549a707a7 |
14 | 24583b132b8d1 |
15 | 1027d6dd75c42 |
hex | 775422b5013f |
131203243245887 has 2 divisors, whose sum is σ = 131203243245888. Its totient is φ = 131203243245886.
The previous prime is 131203243245863. The next prime is 131203243245923. The reversal of 131203243245887 is 788542342302131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131203243245887 - 234 = 131186063376703 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131203243245857) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601621622943 + 65601621622944.
It is an arithmetic number, because the mean of its divisors is an integer number (65601621622944).
Almost surely, 2131203243245887 is an apocalyptic number.
131203243245887 is a deficient number, since it is larger than the sum of its proper divisors (1).
131203243245887 is an equidigital number, since it uses as much as digits as its factorization.
131203243245887 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7741440, while the sum is 53.
The spelling of 131203243245887 in words is "one hundred thirty-one trillion, two hundred three billion, two hundred forty-three million, two hundred forty-five thousand, eight hundred eighty-seven".
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