131203243311397 has 2 divisors, whose sum is σ = 131203243311398. Its totient is φ = 131203243311396.

The previous prime is 131203243311379. The next prime is 131203243311571. The reversal of 131203243311397 is 793113342302131.

It is a happy number.

Together with previous prime (131203243311379) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 89945667992961 + 41257575318436 = 9483969^2 + 6423206^2 .

It is an emirp because it is prime and its reverse (793113342302131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131203243311397 - 2¹⁵ = 131203243278629 is a prime.

It is a super-3 number, since 3×131203243311397³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131203243311307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601621655698 + 65601621655699.

It is an arithmetic number, because the mean of its divisors is an integer number (65601621655699).

Almost surely, 2^{131203243311397} is an apocalyptic number.

It is an amenable number.

131203243311397 is a deficient number, since it is larger than the sum of its proper divisors (1).

131203243311397 is an equidigital number, since it uses as much as digits as its factorization.

131203243311397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 244944, while the sum is 43.

The spelling of 131203243311397 in words is "one hundred thirty-one trillion, two hundred three billion, two hundred forty-three million, three hundred eleven thousand, three hundred ninety-seven".