Base | Representation |
---|---|
bin | 111101000110001010… |
… | …1011111110000111101 |
3 | 110112122210110120012221 |
4 | 1322030111133300331 |
5 | 4122201041324003 |
6 | 140135105325341 |
7 | 12323226021331 |
oct | 1721425376075 |
9 | 415583416187 |
10 | 131203464253 |
11 | 50708a31694 |
12 | 21517936851 |
13 | c4ac30ca64 |
14 | 64c925b7c1 |
15 | 362d8357bd |
hex | 1e8c55fc3d |
131203464253 has 4 divisors (see below), whose sum is σ = 138108909760. Its totient is φ = 124298018748.
The previous prime is 131203464251. The next prime is 131203464289. The reversal of 131203464253 is 352464302131.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131203464253 - 21 = 131203464251 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131203464251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3452722725 + ... + 3452722762.
It is an arithmetic number, because the mean of its divisors is an integer number (34527227440).
Almost surely, 2131203464253 is an apocalyptic number.
It is an amenable number.
131203464253 is a deficient number, since it is larger than the sum of its proper divisors (6905445507).
131203464253 is an equidigital number, since it uses as much as digits as its factorization.
131203464253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6905445506.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 131203464253 its reverse (352464302131), we get a palindrome (483667766384).
The spelling of 131203464253 in words is "one hundred thirty-one billion, two hundred three million, four hundred sixty-four thousand, two hundred fifty-three".
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