13120411433300 has 18 divisors (see below), whose sum is σ = 28471292810478. Its totient is φ = 5248164573280.

The previous prime is 13120411433267. The next prime is 13120411433323. The reversal of 13120411433300 is 333411402131.

It can be written as a sum of positive squares in 3 ways, for example, as 3135552016 + 13117275881284 = 55996^2 + 3621778^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13120411433300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 65602057067 + ... + 65602057266.

It is an arithmetic number, because the mean of its divisors is an integer number (1581738489471).

Almost surely, 2^{13120411433300} is an apocalyptic number.

13120411433300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13120411433300 is an abundant number, since it is smaller than the sum of its proper divisors (15350881377178).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13120411433300 is a wasteful number, since it uses less digits than its factorization.

13120411433300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131204114347 (or 131204114340 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 13120411433300 its reverse (333411402131), we get a palindrome (13453822835431).

The spelling of 13120411433300 in words is "thirteen trillion, one hundred twenty billion, four hundred eleven million, four hundred thirty-three thousand, three hundred".