Base | Representation |
---|---|
bin | 10011000101111100000… |
… | …000101000010010101101 |
3 | 11122102121201012120010221 |
4 | 103011330000220102231 |
5 | 132444032131040401 |
6 | 2442425001531341 |
7 | 163535466202105 |
oct | 23057400502255 |
9 | 4572551176127 |
10 | 1312045565101 |
11 | 466487575577 |
12 | 1923494a3b51 |
13 | 9695782385b |
14 | 47709268205 |
15 | 241e16967a1 |
hex | 1317c0284ad |
1312045565101 has 2 divisors, whose sum is σ = 1312045565102. Its totient is φ = 1312045565100.
The previous prime is 1312045565023. The next prime is 1312045565137. The reversal of 1312045565101 is 1015655402131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1303994989476 + 8050575625 = 1141926^2 + 89725^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312045565101 - 211 = 1312045563053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312045568101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656022782550 + 656022782551.
It is an arithmetic number, because the mean of its divisors is an integer number (656022782551).
Almost surely, 21312045565101 is an apocalyptic number.
It is an amenable number.
1312045565101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312045565101 is an equidigital number, since it uses as much as digits as its factorization.
1312045565101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 34.
The spelling of 1312045565101 in words is "one trillion, three hundred twelve billion, forty-five million, five hundred sixty-five thousand, one hundred one".
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