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13120644463 = 56412325943
BaseRepresentation
bin11000011100000110…
…10010010101101111
31020212101210210112221
430032003102111233
5203332341110323
610005540540211
7643066431523
oct141603222557
936771723487
1013120644463
115623297423
1226620b1667
131311393064
148c67b1d83
1551bd3355d
hex30e0d256f

13120644463 has 4 divisors (see below), whose sum is σ = 13122976048. Its totient is φ = 13118312880.

The previous prime is 13120644457. The next prime is 13120644473. The reversal of 13120644463 is 36444602131.

13120644463 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13120644463 - 213 = 13120636271 is a prime.

It is a super-2 number, since 2×131206444632 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13120644403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1157331 + ... + 1168612.

It is an arithmetic number, because the mean of its divisors is an integer number (3280744012).

Almost surely, 213120644463 is an apocalyptic number.

13120644463 is a deficient number, since it is larger than the sum of its proper divisors (2331585).

13120644463 is an equidigital number, since it uses as much as digits as its factorization.

13120644463 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2331584.

The product of its (nonzero) digits is 41472, while the sum is 34.

The spelling of 13120644463 in words is "thirteen billion, one hundred twenty million, six hundred forty-four thousand, four hundred sixty-three".

Divisors: 1 5641 2325943 13120644463