Base | Representation |
---|---|
bin | 111101000110010111… |
… | …0011110001010100111 |
3 | 110112200020210012002021 |
4 | 1322030232132022213 |
5 | 4122204230330203 |
6 | 140135501524011 |
7 | 12323335460050 |
oct | 1721456361247 |
9 | 415606705067 |
10 | 131210011303 |
11 | 507116a3578 |
12 | 21519b73607 |
13 | c4b0792a57 |
14 | 64ca083727 |
15 | 362e1ca5bd |
hex | 1e8cb9e2a7 |
131210011303 has 8 divisors (see below), whose sum is σ = 158775139872. Its totient is φ = 105850093056.
The previous prime is 131210011271. The next prime is 131210011327. The reversal of 131210011303 is 303110012131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131210011303 - 25 = 131210011271 is a prime.
It is a super-2 number, since 2×1312100113032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131210011363) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 551302450 + ... + 551302687.
It is an arithmetic number, because the mean of its divisors is an integer number (19846892484).
Almost surely, 2131210011303 is an apocalyptic number.
131210011303 is a deficient number, since it is larger than the sum of its proper divisors (27565128569).
131210011303 is a wasteful number, since it uses less digits than its factorization.
131210011303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1102605161.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131210011303 its reverse (303110012131), we get a palindrome (434320023434).
The spelling of 131210011303 in words is "one hundred thirty-one billion, two hundred ten million, eleven thousand, three hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •