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131210011303 = 7171102605137
BaseRepresentation
bin111101000110010111…
…0011110001010100111
3110112200020210012002021
41322030232132022213
54122204230330203
6140135501524011
712323335460050
oct1721456361247
9415606705067
10131210011303
11507116a3578
1221519b73607
13c4b0792a57
1464ca083727
15362e1ca5bd
hex1e8cb9e2a7

131210011303 has 8 divisors (see below), whose sum is σ = 158775139872. Its totient is φ = 105850093056.

The previous prime is 131210011271. The next prime is 131210011327. The reversal of 131210011303 is 303110012131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131210011303 - 25 = 131210011271 is a prime.

It is a super-2 number, since 2×1312100113032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131210011363) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 551302450 + ... + 551302687.

It is an arithmetic number, because the mean of its divisors is an integer number (19846892484).

Almost surely, 2131210011303 is an apocalyptic number.

131210011303 is a deficient number, since it is larger than the sum of its proper divisors (27565128569).

131210011303 is a wasteful number, since it uses less digits than its factorization.

131210011303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1102605161.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 131210011303 its reverse (303110012131), we get a palindrome (434320023434).

The spelling of 131210011303 in words is "one hundred thirty-one billion, two hundred ten million, eleven thousand, three hundred three".

Divisors: 1 7 17 119 1102605137 7718235959 18744287329 131210011303