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13121001223151 is a prime number
BaseRepresentation
bin1011111011101111100010…
…0111011111001111101111
31201110100121010122112201212
42332323320213133033233
53204433302303120101
643523412120425035
72522650433130623
oct276737047371757
951410533575655
1013121001223151
1141a9649143668
12157ab3091817b
137423c741a603
143350ba317183
1517b4924b11bb
hexbeef89df3ef

13121001223151 has 2 divisors, whose sum is σ = 13121001223152. Its totient is φ = 13121001223150.

The previous prime is 13121001223139. The next prime is 13121001223277. The reversal of 13121001223151 is 15132210012131.

It is a weak prime.

It is an emirp because it is prime and its reverse (15132210012131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13121001223151 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121001223111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560500611575 + 6560500611576.

It is an arithmetic number, because the mean of its divisors is an integer number (6560500611576).

Almost surely, 213121001223151 is an apocalyptic number.

13121001223151 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121001223151 is an equidigital number, since it uses as much as digits as its factorization.

13121001223151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 13121001223151 its reverse (15132210012131), we get a palindrome (28253211235282).

The spelling of 13121001223151 in words is "thirteen trillion, one hundred twenty-one billion, one million, two hundred twenty-three thousand, one hundred fifty-one".