Base | Representation |
---|---|
bin | 1011111011101111100010… |
… | …0111011111001111101111 |
3 | 1201110100121010122112201212 |
4 | 2332323320213133033233 |
5 | 3204433302303120101 |
6 | 43523412120425035 |
7 | 2522650433130623 |
oct | 276737047371757 |
9 | 51410533575655 |
10 | 13121001223151 |
11 | 41a9649143668 |
12 | 157ab3091817b |
13 | 7423c741a603 |
14 | 3350ba317183 |
15 | 17b4924b11bb |
hex | beef89df3ef |
13121001223151 has 2 divisors, whose sum is σ = 13121001223152. Its totient is φ = 13121001223150.
The previous prime is 13121001223139. The next prime is 13121001223277. The reversal of 13121001223151 is 15132210012131.
It is a weak prime.
It is an emirp because it is prime and its reverse (15132210012131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13121001223151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13121001223111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560500611575 + 6560500611576.
It is an arithmetic number, because the mean of its divisors is an integer number (6560500611576).
Almost surely, 213121001223151 is an apocalyptic number.
13121001223151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121001223151 is an equidigital number, since it uses as much as digits as its factorization.
13121001223151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 360, while the sum is 23.
Adding to 13121001223151 its reverse (15132210012131), we get a palindrome (28253211235282).
The spelling of 13121001223151 in words is "thirteen trillion, one hundred twenty-one billion, one million, two hundred twenty-three thousand, one hundred fifty-one".
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