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1312100123207 = 10559124263673
BaseRepresentation
bin10011000101111111010…
…000110000001001000111
311122102202111212101210112
4103011333100300021013
5132444140112420312
62442434231143235
7163540031012456
oct23057720601107
94572674771715
101312100123207
11466505349915
12192363814b1b
1396965c16863
14477125cab9d
15241e6371d22
hex1317f430247

1312100123207 has 4 divisors (see below), whose sum is σ = 1312224397440. Its totient is φ = 1311975848976.

The previous prime is 1312100123203. The next prime is 1312100123227. The reversal of 1312100123207 is 7023210012131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312100123207 - 22 = 1312100123203 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312100123203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62121278 + ... + 62142395.

It is an arithmetic number, because the mean of its divisors is an integer number (328056099360).

Almost surely, 21312100123207 is an apocalyptic number.

1312100123207 is a deficient number, since it is larger than the sum of its proper divisors (124274233).

1312100123207 is a wasteful number, since it uses less digits than its factorization.

1312100123207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 124274232.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 1312100123207 its reverse (7023210012131), we get a palindrome (8335310135338).

The spelling of 1312100123207 in words is "one trillion, three hundred twelve billion, one hundred million, one hundred twenty-three thousand, two hundred seven".

Divisors: 1 10559 124263673 1312100123207