Base | Representation |
---|---|
bin | 10011000101111111010… |
… | …001000010111100100111 |
3 | 11122102202112000022110021 |
4 | 103011333101002330213 |
5 | 132444140122401411 |
6 | 2442434232540011 |
7 | 163540031453152 |
oct | 23057721027447 |
9 | 4572675008407 |
10 | 1312100200231 |
11 | 4665053a1777 |
12 | 192363851607 |
13 | 96965c42932 |
14 | 4771260ac99 |
15 | 241e6389a71 |
hex | 1317f442f27 |
1312100200231 has 4 divisors (see below), whose sum is σ = 1326842899200. Its totient is φ = 1297357501264.
The previous prime is 1312100200219. The next prime is 1312100200249. The reversal of 1312100200231 is 1320020012131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1312100200231 - 25 = 1312100200199 is a prime.
It is a super-2 number, since 2×13121002002312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312100260231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7371349351 + ... + 7371349528.
It is an arithmetic number, because the mean of its divisors is an integer number (331710724800).
Almost surely, 21312100200231 is an apocalyptic number.
1312100200231 is a deficient number, since it is larger than the sum of its proper divisors (14742698969).
1312100200231 is an equidigital number, since it uses as much as digits as its factorization.
1312100200231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14742698968.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1312100200231 its reverse (1320020012131), we get a palindrome (2632120212362).
The spelling of 1312100200231 in words is "one trillion, three hundred twelve billion, one hundred million, two hundred thousand, two hundred thirty-one".
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