Base | Representation |
---|---|
bin | 10011000101111111010… |
… | …001000011101011010111 |
3 | 11122102202112000110120002 |
4 | 103011333101003223113 |
5 | 132444140123000343 |
6 | 2442434233001515 |
7 | 163540031464655 |
oct | 23057721035327 |
9 | 4572675013502 |
10 | 1312100203223 |
11 | 4665053a3a47 |
12 | 19236385329b |
13 | 96965c440c4 |
14 | 4771260bdd5 |
15 | 241e638a8b8 |
hex | 1317f443ad7 |
1312100203223 has 2 divisors, whose sum is σ = 1312100203224. Its totient is φ = 1312100203222.
The previous prime is 1312100203163. The next prime is 1312100203273. The reversal of 1312100203223 is 3223020012131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312100203223 - 230 = 1311026461399 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1312100203195 and 1312100203204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312100203273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656050101611 + 656050101612.
It is an arithmetic number, because the mean of its divisors is an integer number (656050101612).
Almost surely, 21312100203223 is an apocalyptic number.
1312100203223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312100203223 is an equidigital number, since it uses as much as digits as its factorization.
1312100203223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1312100203223 its reverse (3223020012131), we get a palindrome (4535120215354).
The spelling of 1312100203223 in words is "one trillion, three hundred twelve billion, one hundred million, two hundred three thousand, two hundred twenty-three".
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