Base | Representation |
---|---|
bin | 1011111011101111100010… |
… | …1111000111100011110111 |
3 | 1201110100121021102011101222 |
4 | 2332323320233013203313 |
5 | 3204433303311121122 |
6 | 43523412231340555 |
7 | 2522650456131131 |
oct | 276737057074367 |
9 | 51410537364358 |
10 | 13121003223287 |
11 | 41a964a28a373 |
12 | 157ab3152175b |
13 | 7423c796ab1b |
14 | 3350ba6b8051 |
15 | 17b492758b42 |
hex | beef8bc78f7 |
13121003223287 has 2 divisors, whose sum is σ = 13121003223288. Its totient is φ = 13121003223286.
The previous prime is 13121003223271. The next prime is 13121003223311. The reversal of 13121003223287 is 78232230012131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13121003223287 - 24 = 13121003223271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13121003223217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560501611643 + 6560501611644.
It is an arithmetic number, because the mean of its divisors is an integer number (6560501611644).
Almost surely, 213121003223287 is an apocalyptic number.
13121003223287 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121003223287 is an equidigital number, since it uses as much as digits as its factorization.
13121003223287 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 35.
The spelling of 13121003223287 in words is "thirteen trillion, one hundred twenty-one billion, three million, two hundred twenty-three thousand, two hundred eighty-seven".
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