13121003223311 has 2 divisors, whose sum is σ = 13121003223312. Its totient is φ = 13121003223310.

The previous prime is 13121003223287. The next prime is 13121003223313. The reversal of 13121003223311 is 11332230012131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13121003223311 is a prime.

It is a super-2 number, since 2×13121003223311² (a number of 27 digits) contains 22 as substring.

Together with 13121003223313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121003223313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560501611655 + 6560501611656.

It is an arithmetic number, because the mean of its divisors is an integer number (6560501611656).

Almost surely, 2^{13121003223311} is an apocalyptic number.

13121003223311 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121003223311 is an equidigital number, since it uses as much as digits as its factorization.

13121003223311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 13121003223311 its reverse (11332230012131), we get a palindrome (24453233235442).

The spelling of 13121003223311 in words is "thirteen trillion, one hundred twenty-one billion, three million, two hundred twenty-three thousand, three hundred eleven".