131210103443130 has 24 divisors (see below), whose sum is σ = 341146268952372. Its totient is φ = 34989360918144.

The previous prime is 131210103443101. The next prime is 131210103443137. The reversal of 131210103443130 is 31344301012131.

131210103443130 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 1 + 0 + 1 + 0 + 344 + 313 + 0 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 128620163612889 + 2589939830241 = 11341083^2 + 1609329^2 .

It is a super-2 number, since 2×131210103443130² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131210103443094 and 131210103443103.

It is not an unprimeable number, because it can be changed into a prime (131210103443137) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 728945019039 + ... + 728945019218.

Almost surely, 2^{131210103443130} is an apocalyptic number.

131210103443130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131210103443130 is an abundant number, since it is smaller than the sum of its proper divisors (209936165509242).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131210103443130 is a wasteful number, since it uses less digits than its factorization.

131210103443130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1457890038270 (or 1457890038267 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 131210103443130 its reverse (31344301012131), we get a palindrome (162554404455261).

The spelling of 131210103443130 in words is "one hundred thirty-one trillion, two hundred ten billion, one hundred three million, four hundred forty-three thousand, one hundred thirty".