Base | Representation |
---|---|
bin | 10011000101111111010… |
… | …100011110011000101101 |
3 | 11122102202120200222101222 |
4 | 103011333110132120231 |
5 | 132444140340132203 |
6 | 2442434304113125 |
7 | 163540042215503 |
oct | 23057724363055 |
9 | 4572676628358 |
10 | 1312101099053 |
11 | 466505955aa8 |
12 | 1923640057a5 |
13 | 96966198a94 |
14 | 477127a2673 |
15 | 241e64b6038 |
hex | 1317f51e62d |
1312101099053 has 2 divisors, whose sum is σ = 1312101099054. Its totient is φ = 1312101099052.
The previous prime is 1312101099041. The next prime is 1312101099097. The reversal of 1312101099053 is 3509901012131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1176958105129 + 135142993924 = 1084877^2 + 367618^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312101099053 - 218 = 1312100836909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312101099853) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656050549526 + 656050549527.
It is an arithmetic number, because the mean of its divisors is an integer number (656050549527).
Almost surely, 21312101099053 is an apocalyptic number.
It is an amenable number.
1312101099053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312101099053 is an equidigital number, since it uses as much as digits as its factorization.
1312101099053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7290, while the sum is 35.
The spelling of 1312101099053 in words is "one trillion, three hundred twelve billion, one hundred one million, ninety-nine thousand, fifty-three".
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