Base | Representation |
---|---|
bin | 11101110101010111001000… |
… | …000011100101111000011110 |
3 | 122012120120202021011001001212 |
4 | 131311113020003211320132 |
5 | 114144222204422412202 |
6 | 1143021104011104422 |
7 | 36431426566460231 |
oct | 3565271003457036 |
9 | 565516667131055 |
10 | 131210312310302 |
11 | 38897a87720715 |
12 | 12871530142112 |
13 | 582a105478444 |
14 | 2458882105418 |
15 | 1028134783652 |
hex | 7755c80e5e1e |
131210312310302 has 4 divisors (see below), whose sum is σ = 196815468465456. Its totient is φ = 65605156155150.
The previous prime is 131210312310257. The next prime is 131210312310353. The reversal of 131210312310302 is 203013213012131.
131210312310302 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1312103123103022 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32802578077574 + ... + 32802578077577.
It is an arithmetic number, because the mean of its divisors is an integer number (49203867116364).
Almost surely, 2131210312310302 is an apocalyptic number.
131210312310302 is a deficient number, since it is larger than the sum of its proper divisors (65605156155154).
131210312310302 is an equidigital number, since it uses as much as digits as its factorization.
131210312310302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65605156155153.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 131210312310302 its reverse (203013213012131), we get a palindrome (334223525322433).
The spelling of 131210312310302 in words is "one hundred thirty-one trillion, two hundred ten billion, three hundred twelve million, three hundred ten thousand, three hundred two".
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