1312104113 has 2 divisors, whose sum is σ = 1312104114. Its totient is φ = 1312104112.

The previous prime is 1312104091. The next prime is 1312104121. The reversal of 1312104113 is 3114012131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1179785104 + 132319009 = 34348^2 + 11503^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312104113 - 2⁶ = 1312104049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1312104091 and 1312104100.

It is not a weakly prime, because it can be changed into another prime (1312104163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656052056 + 656052057.

It is an arithmetic number, because the mean of its divisors is an integer number (656052057).

Almost surely, 2^1312104113 is an apocalyptic number.

It is an amenable number.

1312104113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312104113 is an equidigital number, since it uses as much as digits as its factorization.

1312104113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1312104113 is about 36222.9776937236. The cubic root of 1312104113 is about 1094.7696916994.

Adding to 1312104113 its reverse (3114012131), we get a palindrome (4426116244).

The spelling of 1312104113 in words is "one billion, three hundred twelve million, one hundred four thousand, one hundred thirteen".