Search a number
-
+
131211120210000 = 243548352695229
BaseRepresentation
bin11101110101010111111000…
…001101011111000001010000
3122012120122211120100121002220
4131311113320031133001100
5114144230333233210000
61143021320111141040
736431455606505025
oct3565277015370120
9565518746317086
10131211120210000
1138898361767716
1212871716814780
13582a203965bbc
14245891b52954c
15102818066b1a0
hex7755f835f050

131211120210000 has 200 divisors, whose sum is σ = 428670215746080. Its totient is φ = 34568069568000.

The previous prime is 131211120209987. The next prime is 131211120210029. The reversal of 131211120210000 is 12021112131.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 23857615 + ... + 28837614.

Almost surely, 2131211120210000 is an apocalyptic number.

131211120210000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131211120210000 is an abundant number, since it is smaller than the sum of its proper divisors (297459095536080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131211120210000 is an equidigital number, since it uses as much as digits as its factorization.

131211120210000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52695343 (or 52695322 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 131211120210000 its reverse (12021112131), we get a palindrome (131223141322131).

The spelling of 131211120210000 in words is "one hundred thirty-one trillion, two hundred eleven billion, one hundred twenty million, two hundred ten thousand".