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131211133001 = 1310093164077
BaseRepresentation
bin111101000110011001…
…0110000000001001001
3110112200022220011202122
41322030302300001021
54122210022224001
6140135541541025
712323351141234
oct1721462600111
9415608804678
10131211133001
115071229a2a3
122151a414775
13c4b0a96490
1464ca29641b
15362e34cb1b
hex1e8ccb0049

131211133001 has 4 divisors (see below), whose sum is σ = 141304297092. Its totient is φ = 121117968912.

The previous prime is 131211132989. The next prime is 131211133037. The reversal of 131211133001 is 100331112131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 89056883776 + 42154249225 = 298424^2 + 205315^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131211133001 is a prime.

It is a super-2 number, since 2×1312111330012 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131211133061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5046582026 + ... + 5046582051.

It is an arithmetic number, because the mean of its divisors is an integer number (35326074273).

Almost surely, 2131211133001 is an apocalyptic number.

It is an amenable number.

131211133001 is a deficient number, since it is larger than the sum of its proper divisors (10093164091).

131211133001 is a wasteful number, since it uses less digits than its factorization.

131211133001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10093164090.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 131211133001 its reverse (100331112131), we get a palindrome (231542245132).

The spelling of 131211133001 in words is "one hundred thirty-one billion, two hundred eleven million, one hundred thirty-three thousand, one".

Divisors: 1 13 10093164077 131211133001