Base | Representation |
---|---|
bin | 111101000110011001… |
… | …1000101010011101001 |
3 | 110112200100001121101021 |
4 | 1322030303011103221 |
5 | 4122210033021301 |
6 | 140135543452441 |
7 | 12323351653405 |
oct | 1721463052351 |
9 | 415610047337 |
10 | 131211220201 |
11 | 50712349866 |
12 | 2151a457121 |
13 | c4b0ac7089 |
14 | 64ca2ba105 |
15 | 362e3688a1 |
hex | 1e8ccc54e9 |
131211220201 has 2 divisors, whose sum is σ = 131211220202. Its totient is φ = 131211220200.
The previous prime is 131211220199. The next prime is 131211220213. The reversal of 131211220201 is 102022112131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130324610025 + 886610176 = 361005^2 + 29776^2 .
It is a cyclic number.
It is not a de Polignac number, because 131211220201 - 21 = 131211220199 is a prime.
Together with 131211220199, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (131211220291) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605610100 + 65605610101.
It is an arithmetic number, because the mean of its divisors is an integer number (65605610101).
Almost surely, 2131211220201 is an apocalyptic number.
It is an amenable number.
131211220201 is a deficient number, since it is larger than the sum of its proper divisors (1).
131211220201 is an equidigital number, since it uses as much as digits as its factorization.
131211220201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 131211220201 its reverse (102022112131), we get a palindrome (233233332332).
The spelling of 131211220201 in words is "one hundred thirty-one billion, two hundred eleven million, two hundred twenty thousand, two hundred one".
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