Base | Representation |
---|---|
bin | 111101000110011001… |
… | …1000101010011110101 |
3 | 110112200100001121101201 |
4 | 1322030303011103311 |
5 | 4122210033021323 |
6 | 140135543452501 |
7 | 12323351653423 |
oct | 1721463052365 |
9 | 415610047351 |
10 | 131211220213 |
11 | 50712349877 |
12 | 2151a457131 |
13 | c4b0ac7098 |
14 | 64ca2ba113 |
15 | 362e3688ad |
hex | 1e8ccc54f5 |
131211220213 has 2 divisors, whose sum is σ = 131211220214. Its totient is φ = 131211220212.
The previous prime is 131211220201. The next prime is 131211220229. The reversal of 131211220213 is 312022112131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111968536689 + 19242683524 = 334617^2 + 138718^2 .
It is a cyclic number.
It is not a de Polignac number, because 131211220213 - 25 = 131211220181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131211220313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605610106 + 65605610107.
It is an arithmetic number, because the mean of its divisors is an integer number (65605610107).
Almost surely, 2131211220213 is an apocalyptic number.
It is an amenable number.
131211220213 is a deficient number, since it is larger than the sum of its proper divisors (1).
131211220213 is an equidigital number, since it uses as much as digits as its factorization.
131211220213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 131211220213 its reverse (312022112131), we get a palindrome (443233332344).
The spelling of 131211220213 in words is "one hundred thirty-one billion, two hundred eleven million, two hundred twenty thousand, two hundred thirteen".
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