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13121131223309 is a prime number
BaseRepresentation
bin1011111011110000000001…
…0111011001100100001101
31201110100221012021020102112
42332330000113121210031
53204434034043121214
643523433043033405
72522653602122054
oct276740027314415
951410835236375
1013121131223309
1141a970556570a
12157ab6836b865
13742418336195
143350cd6b739b
1517b49dadea3e
hexbef005d990d

13121131223309 has 2 divisors, whose sum is σ = 13121131223310. Its totient is φ = 13121131223308.

The previous prime is 13121131223273. The next prime is 13121131223339. The reversal of 13121131223309 is 90332213112131.

13121131223309 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6918067769284 + 6203063454025 = 2630222^2 + 2490595^2 .

It is an emirp because it is prime and its reverse (90332213112131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13121131223309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121131223339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560565611654 + 6560565611655.

It is an arithmetic number, because the mean of its divisors is an integer number (6560565611655).

Almost surely, 213121131223309 is an apocalyptic number.

It is an amenable number.

13121131223309 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121131223309 is an equidigital number, since it uses as much as digits as its factorization.

13121131223309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 32.

The spelling of 13121131223309 in words is "thirteen trillion, one hundred twenty-one billion, one hundred thirty-one million, two hundred twenty-three thousand, three hundred nine".