Base | Representation |
---|---|
bin | 1011111011110000000001… |
… | …0111011001100100101011 |
3 | 1201110100221012021020110122 |
4 | 2332330000113121210223 |
5 | 3204434034043121324 |
6 | 43523433043033455 |
7 | 2522653602122126 |
oct | 276740027314453 |
9 | 51410835236418 |
10 | 13121131223339 |
11 | 41a9705565737 |
12 | 157ab6836b88b |
13 | 7424183361b9 |
14 | 3350cd6b73bd |
15 | 17b49dadea5e |
hex | bef005d992b |
13121131223339 has 2 divisors, whose sum is σ = 13121131223340. Its totient is φ = 13121131223338.
The previous prime is 13121131223309. The next prime is 13121131223383. The reversal of 13121131223339 is 93332213112131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13121131223339 - 224 = 13121114446123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13121131223299 and 13121131223308.
It is not a weakly prime, because it can be changed into another prime (13121131223309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560565611669 + 6560565611670.
It is an arithmetic number, because the mean of its divisors is an integer number (6560565611670).
Almost surely, 213121131223339 is an apocalyptic number.
13121131223339 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121131223339 is an equidigital number, since it uses as much as digits as its factorization.
13121131223339 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 17496, while the sum is 35.
The spelling of 13121131223339 in words is "thirteen trillion, one hundred twenty-one billion, one hundred thirty-one million, two hundred twenty-three thousand, three hundred thirty-nine".
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