131211313104301 has 4 divisors (see below), whose sum is σ = 136916152804512. Its totient is φ = 125506473404092.

The previous prime is 131211313104259. The next prime is 131211313104331. The reversal of 131211313104301 is 103401313112131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131211313104301 - 2³¹ = 131209165620653 is a prime.

It is a super-2 number, since 2×131211313104301² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131211313104331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2852419850071 + ... + 2852419850116.

It is an arithmetic number, because the mean of its divisors is an integer number (34229038201128).

Almost surely, 2^{131211313104301} is an apocalyptic number.

It is an amenable number.

131211313104301 is a deficient number, since it is larger than the sum of its proper divisors (5704839700211).

131211313104301 is an equidigital number, since it uses as much as digits as its factorization.

131211313104301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5704839700210.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 131211313104301 its reverse (103401313112131), we get a palindrome (234612626216432).

The spelling of 131211313104301 in words is "one hundred thirty-one trillion, two hundred eleven billion, three hundred thirteen million, one hundred four thousand, three hundred one".