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13121132000 = 2553231271123
BaseRepresentation
bin11000011100001010…
…01001010111100000
31020212102201120022212
430032011021113200
5203333002211000
610005555221252
7643103532104
oct141605112740
936772646285
1013121132000
11562359a749
1226622a7828
131311503c42
148c689b904
1551bdccc35
hex30e1495e0

13121132000 has 192 divisors, whose sum is σ = 33935376384. Its totient is φ = 4976294400.

The previous prime is 13121131963. The next prime is 13121132033. The reversal of 13121132000 is 23112131.

It is a super-2 number, since 2×131211320002 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11683439 + ... + 11684561.

It is an arithmetic number, because the mean of its divisors is an integer number (176746752).

Almost surely, 213121132000 is an apocalyptic number.

13121132000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13121132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16967688192).

13121132000 is an abundant number, since it is smaller than the sum of its proper divisors (20814244384).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121132000 is a wasteful number, since it uses less digits than its factorization.

13121132000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1298 (or 1280 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 13121132000 its reverse (23112131), we get a palindrome (13144244131).

The spelling of 13121132000 in words is "thirteen billion, one hundred twenty-one million, one hundred thirty-two thousand".