Base | Representation |
---|---|
bin | 10011000110000000000… |
… | …010111000000110111110 |
3 | 11122102210102120222020221 |
4 | 103012000002320012332 |
5 | 132444201443404123 |
6 | 2442435420531554 |
7 | 163540250500144 |
oct | 23060002700676 |
9 | 4572712528227 |
10 | 1312113263038 |
11 | 466511803a86 |
12 | 1923680b0bba |
13 | 969688675c6 |
14 | 4771424b594 |
15 | 241e75ba25d |
hex | 131800b81be |
1312113263038 has 8 divisors (see below), whose sum is σ = 1971147460680. Its totient is φ = 655064109480.
The previous prime is 1312113262969. The next prime is 1312113263039. The reversal of 1312113263038 is 8303623112131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 1312113262994 and 1312113263012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312113263039) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 496259368 + ... + 496262011.
It is an arithmetic number, because the mean of its divisors is an integer number (246393432585).
Almost surely, 21312113263038 is an apocalyptic number.
1312113263038 is a deficient number, since it is larger than the sum of its proper divisors (659034197642).
1312113263038 is an equidigital number, since it uses as much as digits as its factorization.
1312113263038 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 992522042.
The product of its (nonzero) digits is 15552, while the sum is 34.
Adding to 1312113263038 its reverse (8303623112131), we get a palindrome (9615736375169).
The spelling of 1312113263038 in words is "one trillion, three hundred twelve billion, one hundred thirteen million, two hundred sixty-three thousand, thirty-eight".
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