13121141113100 has 18 divisors (see below), whose sum is σ = 28472876215644. Its totient is φ = 5248456445200.

The previous prime is 13121141113079. The next prime is 13121141113103. The reversal of 13121141113100 is 131114112131.

It is a super-2 number, since 2×13121141113100² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (13121141113103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 65605705466 + ... + 65605705665.

Almost surely, 2^{13121141113100} is an apocalyptic number.

13121141113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13121141113100 is an abundant number, since it is smaller than the sum of its proper divisors (15351735102544).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121141113100 is a wasteful number, since it uses less digits than its factorization.

13121141113100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131211411145 (or 131211411138 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 13121141113100 its reverse (131114112131), we get a palindrome (13252255225231).

The spelling of 13121141113100 in words is "thirteen trillion, one hundred twenty-one billion, one hundred forty-one million, one hundred thirteen thousand, one hundred".