Base | Representation |
---|---|
bin | 10011000110000000000… |
… | …110111011011101010111 |
3 | 11122102210111120221110021 |
4 | 103012000012323131113 |
5 | 132444202231402320 |
6 | 2442435455410011 |
7 | 163540262513212 |
oct | 23060006733527 |
9 | 4572714527407 |
10 | 1312114325335 |
11 | 46651236a110 |
12 | 192368523907 |
13 | 96968b49c98 |
14 | 47714446779 |
15 | 241e7729daa |
hex | 131801bb757 |
1312114325335 has 16 divisors (see below), whose sum is σ = 1717703160192. Its totient is φ = 954250394400.
The previous prime is 1312114325287. The next prime is 1312114325341. The reversal of 1312114325335 is 5335234112131.
It is a de Polignac number, because none of the positive numbers 2k-1312114325335 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1312114325335.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4570180 + ... + 4848790.
It is an arithmetic number, because the mean of its divisors is an integer number (107356447512).
Almost surely, 21312114325335 is an apocalyptic number.
1312114325335 is a deficient number, since it is larger than the sum of its proper divisors (405588834857).
1312114325335 is a wasteful number, since it uses less digits than its factorization.
1312114325335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 364254.
The product of its digits is 32400, while the sum is 34.
Adding to 1312114325335 its reverse (5335234112131), we get a palindrome (6647348437466).
The spelling of 1312114325335 in words is "one trillion, three hundred twelve billion, one hundred fourteen million, three hundred twenty-five thousand, three hundred thirty-five".
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