Base | Representation |
---|---|
bin | 1011111011110000001001… |
… | …1101110101010111000111 |
3 | 1201110101000122120200012011 |
4 | 2332330002131311113013 |
5 | 3204434122103330310 |
6 | 43523440342235051 |
7 | 2522654510506660 |
oct | 276740235652707 |
9 | 51411018520164 |
10 | 13121166464455 |
11 | 41a9723445925 |
12 | 157ab78125a87 |
13 | 74242272492a |
14 | 3350d424c367 |
15 | 17b4a1c5178a |
hex | bef027755c7 |
13121166464455 has 32 divisors (see below), whose sum is σ = 18091263826944. Its totient is φ = 8949217118976.
The previous prime is 13121166464453. The next prime is 13121166464477. The reversal of 13121166464455 is 55446466112131.
It is a cyclic number.
It is not a de Polignac number, because 13121166464455 - 21 = 13121166464453 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13121166464399 and 13121166464408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13121166464453) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4810387 + ... + 7027243.
It is an arithmetic number, because the mean of its divisors is an integer number (565351994592).
Almost surely, 213121166464455 is an apocalyptic number.
13121166464455 is a deficient number, since it is larger than the sum of its proper divisors (4970097362489).
13121166464455 is a wasteful number, since it uses less digits than its factorization.
13121166464455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2217775.
The product of its digits is 2073600, while the sum is 49.
The spelling of 13121166464455 in words is "thirteen trillion, one hundred twenty-one billion, one hundred sixty-six million, four hundred sixty-four thousand, four hundred fifty-five".
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