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131212230041021 is a prime number
BaseRepresentation
bin11101110101011000111010…
…010111001001110110111101
3122012120202200220200212001112
4131311120322113021312331
5114144240121342303041
61143022022154451405
736431525244065003
oct3565307227116675
9565522626625045
10131212230041021
1138898881187138
1212871986433b65
13582a34c87954c
1424589c4aa6a73
1510281e7ce4deb
hex77563a5c9dbd

131212230041021 has 2 divisors, whose sum is σ = 131212230041022. Its totient is φ = 131212230041020.

The previous prime is 131212230040999. The next prime is 131212230041041. The reversal of 131212230041021 is 120140032212131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113988485018521 + 17223745022500 = 10676539^2 + 4150150^2 .

It is a cyclic number.

It is not a de Polignac number, because 131212230041021 - 238 = 130937352134077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131212230041041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606115020510 + 65606115020511.

It is an arithmetic number, because the mean of its divisors is an integer number (65606115020511).

Almost surely, 2131212230041021 is an apocalyptic number.

It is an amenable number.

131212230041021 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212230041021 is an equidigital number, since it uses as much as digits as its factorization.

131212230041021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 131212230041021 its reverse (120140032212131), we get a palindrome (251352262253152).

The spelling of 131212230041021 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred thirty million, forty-one thousand, twenty-one".