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1312123012433 is a prime number
BaseRepresentation
bin10011000110000000101…
…000000100010101010001
311122102211002221021220122
4103012000220010111101
5132444211442344213
62442440405520025
7163540426404062
oct23060050042521
94572732837818
101312123012433
11466517262932
1219236b413015
139696a89c08c
1447715668569
15241e8393d08
hex13180a04551

1312123012433 has 2 divisors, whose sum is σ = 1312123012434. Its totient is φ = 1312123012432.

The previous prime is 1312123012429. The next prime is 1312123012511. The reversal of 1312123012433 is 3342103212131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 932244318784 + 379878693649 = 965528^2 + 616343^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312123012433 - 22 = 1312123012429 is a prime.

It is not a weakly prime, because it can be changed into another prime (1312123012633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656061506216 + 656061506217.

It is an arithmetic number, because the mean of its divisors is an integer number (656061506217).

Almost surely, 21312123012433 is an apocalyptic number.

It is an amenable number.

1312123012433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312123012433 is an equidigital number, since it uses as much as digits as its factorization.

1312123012433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 1312123012433 its reverse (3342103212131), we get a palindrome (4654226224564).

The spelling of 1312123012433 in words is "one trillion, three hundred twelve billion, one hundred twenty-three million, twelve thousand, four hundred thirty-three".