Base | Representation |
---|---|
bin | 1011111011110000011100… |
… | …1110110010000000010111 |
3 | 1201110101020020000001111102 |
4 | 2332330013032302000113 |
5 | 3204434303034422011 |
6 | 43523452315500315 |
7 | 2522656501133501 |
oct | 276740716620027 |
9 | 51411206001442 |
10 | 13121246404631 |
11 | 41a9764586092 |
12 | 157ab9aa5769b |
13 | 742436163a01 |
14 | 335100adad71 |
15 | 17b4a8c9273b |
hex | bef073b2017 |
13121246404631 has 2 divisors, whose sum is σ = 13121246404632. Its totient is φ = 13121246404630.
The previous prime is 13121246404621. The next prime is 13121246404649. The reversal of 13121246404631 is 13640464212131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13121246404631 - 210 = 13121246403607 is a prime.
It is a super-2 number, since 2×131212464046312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13121246404601) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560623202315 + 6560623202316.
It is an arithmetic number, because the mean of its divisors is an integer number (6560623202316).
Almost surely, 213121246404631 is an apocalyptic number.
13121246404631 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121246404631 is an equidigital number, since it uses as much as digits as its factorization.
13121246404631 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 38.
The spelling of 13121246404631 in words is "thirteen trillion, one hundred twenty-one billion, two hundred forty-six million, four hundred four thousand, six hundred thirty-one".
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