131213011103429 has 2 divisors, whose sum is σ = 131213011103430. Its totient is φ = 131213011103428.

The previous prime is 131213011103423. The next prime is 131213011103431. The reversal of 131213011103429 is 924301110312131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90255187074529 + 40957824028900 = 9500273^2 + 6399830^2 .

It is an emirp because it is prime and its reverse (924301110312131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131213011103429 - 2⁴ = 131213011103413 is a prime.

Together with 131213011103431, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131213011103395 and 131213011103404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131213011103423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606505551714 + 65606505551715.

It is an arithmetic number, because the mean of its divisors is an integer number (65606505551715).

Almost surely, 2^{131213011103429} is an apocalyptic number.

It is an amenable number.

131213011103429 is a deficient number, since it is larger than the sum of its proper divisors (1).

131213011103429 is an equidigital number, since it uses as much as digits as its factorization.

131213011103429 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 32.

The spelling of 131213011103429 in words is "one hundred thirty-one trillion, two hundred thirteen billion, eleven million, one hundred three thousand, four hundred twenty-nine".