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131213202120 = 2332571113237757
BaseRepresentation
bin111101000110011101…
…0101001001011001000
3110112200110210022001200
41322030322221023020
54122211034431440
6140140054144200
712323404546530
oct1721472511310
9415613708050
10131213202120
1150713482910
122151b052060
13c4b133c200
1464ca6744c0
15362e60ac30
hex1e8cea92c8

131213202120 has 1152 divisors, whose sum is σ = 592053546240. Its totient is φ = 24455208960.

The previous prime is 131213202103. The next prime is 131213202137. The reversal of 131213202120 is 21202312131.

131213202120 is a `hidden beast` number, since 13 + 121 + 320 + 212 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (131213202103) and next prime (131213202137).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 131213202093 and 131213202102.

It is an unprimeable number.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 173332782 + ... + 173333538.

It is an arithmetic number, because the mean of its divisors is an integer number (513935370).

Almost surely, 2131213202120 is an apocalyptic number.

131213202120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131213202120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (296026773120).

131213202120 is an abundant number, since it is smaller than the sum of its proper divisors (460840344120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131213202120 is a wasteful number, since it uses less digits than its factorization.

131213202120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 855 (or 835 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 131213202120 its reverse (21202312131), we get a palindrome (152415514251).

It can be divided in two parts, 131213 and 202120, that added together give a palindrome (333333).

The spelling of 131213202120 in words is "one hundred thirty-one billion, two hundred thirteen million, two hundred two thousand, one hundred twenty".