Base | Representation |
---|---|
bin | 1011111011110000101110… |
… | …1111111101101100110101 |
3 | 1201110101102111122110212021 |
4 | 2332330023233331230311 |
5 | 3204434431441242044 |
6 | 43523504024353141 |
7 | 2522661411365614 |
oct | 276741357755465 |
9 | 51411374573767 |
10 | 13121322212149 |
11 | 41a97a3353428 |
12 | 157b0003157b1 |
13 | 742448a86a28 |
14 | 33510abd187b |
15 | 17b4b0768e84 |
hex | bef0bbfdb35 |
13121322212149 has 2 divisors, whose sum is σ = 13121322212150. Its totient is φ = 13121322212148.
The previous prime is 13121322212107. The next prime is 13121322212221. The reversal of 13121322212149 is 94121222312131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12399680457124 + 721641755025 = 3521318^2 + 849495^2 .
It is a cyclic number.
It is not a de Polignac number, because 13121322212149 - 221 = 13121320114997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13121322212549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560661106074 + 6560661106075.
It is an arithmetic number, because the mean of its divisors is an integer number (6560661106075).
Almost surely, 213121322212149 is an apocalyptic number.
It is an amenable number.
13121322212149 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121322212149 is an equidigital number, since it uses as much as digits as its factorization.
13121322212149 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10368, while the sum is 34.
The spelling of 13121322212149 in words is "thirteen trillion, one hundred twenty-one billion, three hundred twenty-two million, two hundred twelve thousand, one hundred forty-nine".
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