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13121322212221 is a prime number
BaseRepresentation
bin1011111011110000101110…
…1111111101101101111101
31201110101102111122110221221
42332330023233331231331
53204434431441242341
643523504024353341
72522661411366046
oct276741357755575
951411374573857
1013121322212221
1141a97a3353493
12157b000315851
13742448a86a82
1433510abd18cd
1517b4b0768ed1
hexbef0bbfdb7d

13121322212221 has 2 divisors, whose sum is σ = 13121322212222. Its totient is φ = 13121322212220.

The previous prime is 13121322212149. The next prime is 13121322212269. The reversal of 13121322212221 is 12221222312131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11083605932025 + 2037716280196 = 3329205^2 + 1427486^2 .

It is a cyclic number.

It is not a de Polignac number, because 13121322212221 - 29 = 13121322211709 is a prime.

It is a super-3 number, since 3×131213222122213 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121322212281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560661106110 + 6560661106111.

It is an arithmetic number, because the mean of its divisors is an integer number (6560661106111).

Almost surely, 213121322212221 is an apocalyptic number.

It is an amenable number.

13121322212221 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121322212221 is an equidigital number, since it uses as much as digits as its factorization.

13121322212221 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 25.

Adding to 13121322212221 its reverse (12221222312131), we get a palindrome (25342544524352).

The spelling of 13121322212221 in words is "thirteen trillion, one hundred twenty-one billion, three hundred twenty-two million, two hundred twelve thousand, two hundred twenty-one".