Base | Representation |
---|---|
bin | 11000011100001011… |
… | …11001111111001101 |
3 | 1020212110002200111202 |
4 | 30032011321333031 |
5 | 203333030044044 |
6 | 10010003355245 |
7 | 643105321523 |
oct | 141605717715 |
9 | 36773080452 |
10 | 13121331149 |
11 | 5623716333 |
12 | 2662382b25 |
13 | 1311573794 |
14 | 8c6910313 |
15 | 51be1bc4e |
hex | 30e179fcd |
13121331149 has 2 divisors, whose sum is σ = 13121331150. Its totient is φ = 13121331148.
The previous prime is 13121331101. The next prime is 13121331217. The reversal of 13121331149 is 94113312131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8790375049 + 4330956100 = 93757^2 + 65810^2 .
It is a cyclic number.
It is not a de Polignac number, because 13121331149 - 232 = 8826363853 is a prime.
It is a super-2 number, since 2×131213311492 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13121331749) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560665574 + 6560665575.
It is an arithmetic number, because the mean of its divisors is an integer number (6560665575).
Almost surely, 213121331149 is an apocalyptic number.
It is an amenable number.
13121331149 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121331149 is an equidigital number, since it uses as much as digits as its factorization.
13121331149 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1944, while the sum is 29.
The spelling of 13121331149 in words is "thirteen billion, one hundred twenty-one million, three hundred thirty-one thousand, one hundred forty-nine".
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