131213513105041 has 2 divisors, whose sum is σ = 131213513105042. Its totient is φ = 131213513105040.

The previous prime is 131213513104969. The next prime is 131213513105113. The reversal of 131213513105041 is 140501315312131.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (131213513104969) and next prime (131213513105113).

It can be written as a sum of positive squares in only one way, i.e., 130982989248400 + 230523856641 = 11444780^2 + 480129^2 .

It is a cyclic number.

It is not a de Polignac number, because 131213513105041 - 2⁹ = 131213513104529 is a prime.

It is a super-2 number, since 2×131213513105041² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131213513104994 and 131213513105012.

It is not a weakly prime, because it can be changed into another prime (131213513102041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606756552520 + 65606756552521.

It is an arithmetic number, because the mean of its divisors is an integer number (65606756552521).

Almost surely, 2^{131213513105041} is an apocalyptic number.

It is an amenable number.

131213513105041 is a deficient number, since it is larger than the sum of its proper divisors (1).

131213513105041 is an equidigital number, since it uses as much as digits as its factorization.

131213513105041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 31.

Adding to 131213513105041 its reverse (140501315312131), we get a palindrome (271714828417172).

The spelling of 131213513105041 in words is "one hundred thirty-one trillion, two hundred thirteen billion, five hundred thirteen million, one hundred five thousand, forty-one".