Search a number
-
+
13121404031447 is a prime number
BaseRepresentation
bin1011111011110001000010…
…1000000101000111010111
31201110101122012121022211122
42332330100220011013113
53204440113413001242
643523520110154155
72522663424010055
oct276742050050727
951411565538748
1013121404031447
1141a9835557488
12157b0237b295b
1374245ca0320a
14335117a0d1d5
1517b4b7a2bad2
hexbef10a051d7

13121404031447 has 2 divisors, whose sum is σ = 13121404031448. Its totient is φ = 13121404031446.

The previous prime is 13121404031377. The next prime is 13121404031471. The reversal of 13121404031447 is 74413040412131.

It is a happy number.

13121404031447 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (74413040412131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13121404031447 - 220 = 13121402982871 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121404031947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560702015723 + 6560702015724.

It is an arithmetic number, because the mean of its divisors is an integer number (6560702015724).

Almost surely, 213121404031447 is an apocalyptic number.

13121404031447 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121404031447 is an equidigital number, since it uses as much as digits as its factorization.

13121404031447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32256, while the sum is 35.

Adding to 13121404031447 its reverse (74413040412131), we get a palindrome (87534444443578).

The spelling of 13121404031447 in words is "thirteen trillion, one hundred twenty-one billion, four hundred four million, thirty-one thousand, four hundred forty-seven".