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131214433 = 718744919
BaseRepresentation
bin1111101001000…
…10110001100001
3100010220101100211
413310202301201
5232042330213
621004214121
73152206240
oct764426141
9303811324
10131214433
1168081389
1237b3a341
132125249c
14135d8957
15b7bd53d
hex7d22c61

131214433 has 4 divisors (see below), whose sum is σ = 149959360. Its totient is φ = 112469508.

The previous prime is 131214427. The next prime is 131214439. The reversal of 131214433 is 334412131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334412131 = 2557130783.

It is an interprime number because it is at equal distance from previous prime (131214427) and next prime (131214439).

It is a cyclic number.

It is not a de Polignac number, because 131214433 - 217 = 131083361 is a prime.

It is a super-2 number, since 2×1312144332 = 34434454855022978, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131214439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9372453 + ... + 9372466.

It is an arithmetic number, because the mean of its divisors is an integer number (37489840).

Almost surely, 2131214433 is an apocalyptic number.

It is an amenable number.

131214433 is a deficient number, since it is larger than the sum of its proper divisors (18744927).

131214433 is an equidigital number, since it uses as much as digits as its factorization.

131214433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18744926.

The product of its digits is 864, while the sum is 22.

The square root of 131214433 is about 11454.8868610737. The cubic root of 131214433 is about 508.1522692835.

Adding to 131214433 its reverse (334412131), we get a palindrome (465626564).

The spelling of 131214433 in words is "one hundred thirty-one million, two hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 7 18744919 131214433