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131220001023 = 343740000341
BaseRepresentation
bin111101000110101010…
…0100101000011111111
3110112200221120201101220
41322031110211003333
54122214310013043
6140140500004423
712323516414436
oct1721524450377
9415627521356
10131220001023
11507172a6a41
1221521390713
13c4b287ca27
1464cb52411d
153630000483
hex1e8d5250ff

131220001023 has 4 divisors (see below), whose sum is σ = 174960001368. Its totient is φ = 87480000680.

The previous prime is 131220001021. The next prime is 131220001037. The reversal of 131220001023 is 320100022131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131220001023 - 21 = 131220001021 is a prime.

It is a super-2 number, since 2×1312200010232 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131220000993 and 131220001011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131220001021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21870000168 + ... + 21870000173.

It is an arithmetic number, because the mean of its divisors is an integer number (43740000342).

Almost surely, 2131220001023 is an apocalyptic number.

131220001023 is a deficient number, since it is larger than the sum of its proper divisors (43740000345).

131220001023 is an equidigital number, since it uses as much as digits as its factorization.

131220001023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43740000344.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 131220001023 its reverse (320100022131), we get a palindrome (451320023154).

The spelling of 131220001023 in words is "one hundred thirty-one billion, two hundred twenty million, one thousand, twenty-three".

Divisors: 1 3 43740000341 131220001023