Base | Representation |
---|---|
bin | 10011000110000101010… |
… | …001111100111110111111 |
3 | 11122110000112212121121221 |
4 | 103012011101330332333 |
5 | 132444341440214442 |
6 | 2442452235334211 |
7 | 163542365220211 |
oct | 23060521747677 |
9 | 4573015777557 |
10 | 1312201101247 |
11 | 466557349143 |
12 | 1923915b1367 |
13 | 96980b1058a |
14 | 47721b945b1 |
15 | 2420016b467 |
hex | 1318547cfbf |
1312201101247 has 2 divisors, whose sum is σ = 1312201101248. Its totient is φ = 1312201101246.
The previous prime is 1312201101227. The next prime is 1312201101293. The reversal of 1312201101247 is 7421011022131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312201101247 is a prime.
It is a super-2 number, since 2×13122011012472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312201101227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656100550623 + 656100550624.
It is an arithmetic number, because the mean of its divisors is an integer number (656100550624).
Almost surely, 21312201101247 is an apocalyptic number.
1312201101247 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312201101247 is an equidigital number, since it uses as much as digits as its factorization.
1312201101247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 1312201101247 its reverse (7421011022131), we get a palindrome (8733212123378).
The spelling of 1312201101247 in words is "one trillion, three hundred twelve billion, two hundred one million, one hundred one thousand, two hundred forty-seven".
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